I have been looking for an elegant and efficient way to chunk a string into substrings of a given length in Ruby.
So far, the best I could come up with is this:
def chunk(string, size) (0..(string.length-1)/size).map{|i|string[i*size,size]} end >> chunk("abcdef",3) => ["abc", "def"] >> chunk("abcde",3) => ["abc", "de"] >> chunk("abc",3) => ["abc"] >> chunk("ab",3) => ["ab"] >> chunk("",3) => []
You might want chunk("", n)
to return [""]
instead of []
. If so, just add this as the first line of the method:
return [""] if string.empty?
Would you recommend any better solution?
Edit
Thanks to Jeremy Ruten for this elegant and efficient solution: [edit: NOT efficient!]
def chunk(string, size) string.scan(/.{1,#{size}}/) end
Edit
The string.scan solution takes about 60 seconds to chop 512k into 1k chunks 10000 times, compared with the original slice-based solution which only takes 2.4 seconds.
The split() method splits a string into an array of substrings. The split() method returns the new array. The split() method does not change the original string. If (" ") is used as separator, the string is split between words.
Python split() method is used to split the string into chunks, and it accepts one argument called separator. A separator can be any character or a symbol. If no separators are defined, then it will split the given string and whitespace will be used by default.
To split a string into chunks of specific length, use List Comprehension with the string. All the chunks will be returned as an array. We can also use a while loop to split a list into chunks of specific length.
Use String#scan
:
>> 'abcdefghijklmnopqrstuvwxyz'.scan(/.{4}/) => ["abcd", "efgh", "ijkl", "mnop", "qrst", "uvwx"] >> 'abcdefghijklmnopqrstuvwxyz'.scan(/.{1,4}/) => ["abcd", "efgh", "ijkl", "mnop", "qrst", "uvwx", "yz"] >> 'abcdefghijklmnopqrstuvwxyz'.scan(/.{1,3}/) => ["abc", "def", "ghi", "jkl", "mno", "pqr", "stu", "vwx", "yz"]
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