So normally we can get z-Index value of a div element using, e.g:
var zindex = document.getElementById('id').style.zIndex;
I am using this value in my code to do something. Now the problem is with default values where there is nothing defined in HTML code (or even in cases where z-Index is defined in external css), the same java script command returns nothing.
I understand that in default case, normally the browser decides the rendering based upon element stack. But is there any specific value or way to realize this in JavaScript that there is no value defined??
I mean, normally nothing returned would mean there is no value defined. But it also happend with external css, so how can i distinguish the both??
The Default z-index Value of HTML Elements The default z-index value of all the elements on a web page is auto, which corresponds to 0 where no z-index is assigned. An element with z-index: -1 will be displayed behind all other elements on the page, assuming they are given no z-index values.
Definition and Usage The zIndex property sets or returns the stack order of a positioned element. An element with greater stack order (1) is always in front of another element with lower stack order (0).
In CSS code bases, you'll often see z-index values of 999, 9999 or 99999. This is a perhaps lazy way to ensure that the element is always on top. It can lead to problems down the road when multiple elements need to be on top.
The z-index property determines the stack level of an HTML element. The “stack level” refers to the element's position on the Z axis (as opposed to the X axis or Y axis). A higher value means the element will be closer to the top of the stacking order. This stacking order runs perpendicular to the display, or viewport.
Default z-index
of any element is 'auto'
with exception of <html> which has default z-index:0
. 'Auto' means that element gets z-index from its parent.
You can see this by using Developer Tools (in Chrome) or any similar tool in other browser. Also you can get this in your code by window.getComputedStyle() as others proposed here.
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