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What is a view of a collection?

I've been reading the term view a few times when using Guava collections and reading its documentation.

I've looked for an explanation of what a view is in this context and whether it's a term used outside of Guava. It's quite often used here. This type from Guava has view in its name.

My guess is that a view of a collection is another collection with the same data but structured differently; for instance when I add the entries from a java.util.HashSet to a java.util.LinkedHashSet the latter would be a view of the former. Is that correct?

Can somebody hook me up with a link to an accepted definition of view, if there is one?

Thanks.

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Matthias Braun Avatar asked Sep 19 '13 18:09

Matthias Braun


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1 Answers

A view of another object doesn't contain its own data at all. All of its operations are implemented in terms of operations on the other object.

For example, the keySet() view of a Map might have an implementation that looks something like this:

class KeySet implements Set<K> {
  private final Map<K, V> map;

  public boolean contains(Object o) {
    return map.containsKey(o);
  }

  ...
}

In particular, whenever you modify the backing object of your view -- here, the Map backs the keySet() -- the view reflects the same changes. For example, if you call map.remove(key), then keySet.contains(key) will return false without you having to do anything else.

Alternately, Arrays.asList(array) provides a List view of that array.

String[] strings = {"a", "b", "c"};
List<String> list = Arrays.asList(strings);
System.out.println(list.get(0)); // "a"
strings[0] = "d";
System.out.println(list.get(0)); // "d"
list.set(0, "e");
System.out.println(strings[0]); // "e"

A view is just another way of looking at the data in the original backing object -- Arrays.asList lets you use the List API to access a normal array; Map.keySet() lets you access the keys of a Map as if it were a perfectly ordinary Set -- all without copying the data or creating another data structure.

Generally, the advantage of using a view instead of making a copy is the efficiency. For example, if you have an array and you need to get it to a method that takes a List, you're not creating a new ArrayList and a whole copy of the data -- the Arrays.asList view takes only constant extra memory, and just implements all the List methods by accessing the original array.

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Louis Wasserman Avatar answered Oct 10 '22 04:10

Louis Wasserman