I'm trying to match a control character in the form \^c where c is any valid character for control characters. I have this regular expression, but it's not currently working: \\[^][@-z]
I think the problem lies with the fact that the caret character (^) is part of the regular expressions parsing engine.
Match an ASCII text string of the form ^X
using the pattern \^.
, nothing more. Match an ASCII text string of the form \^X
with the pattern \\\^.
. You may wish to constrain that dot to [?@_\[\]^\\]
, so \\\^[A-Z?@_\[\]^\\]
. It’s easier to read as [?\x40-\x5F]
for the bracketed character class, hence \\\^[?\x40-\x5F]
for a literal BACKSLASH, followed by a literal CIRCUMFLEX, followed by something that turns into one of the valid control characters.
Note that that is the result of printing out the pattern, or what you’d read from a file. It’s what you need to pass to the regex compiler. If you have it as a string literal, you must of course double each of those backslashes. `\\\\\\^[?\\x40-\\x5F]"
Yes, it is insane looking, but that is because Java does not support regexes directly as Groovy and Scala — or Perl and Ruby — do. Regex work is always easier without the extra bbaacckksslllllaasshheesssssess. :)
If you had real control characters instead of indirect representations of them, you would use \pC
for all literal code points with the property GC=Other, or \p{Cc}
for just GC=Control.
Check this out: http://www.regular-expressions.info/characters.html . You should be able to use \cA to \cZ to find the control characters..
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