What is a good way to handle exceptions when trying to read a file in python?

Question

I want to read a .csv file in python.

• I don't know if the file exists.
• My current solution is below. It feels sloppy to me because the two separate exception tests are awkwardly juxtaposed.

Is there a prettier way to do it?

import csv     fName = "aFile.csv"  try:     with open(fName, 'r') as f:         reader = csv.reader(f)         for row in reader:             pass #do stuff here      except IOError:     print "Could not read file:", fName 

Answer 1

How about this:

try:     f = open(fname, 'rb') except OSError:     print "Could not open/read file:", fname     sys.exit()  with f:     reader = csv.reader(f)     for row in reader:         pass #do stuff here 

Answer 2

Here is a read/write example. The with statements insure the close() statement will be called by the file object regardless of whether an exception is thrown. http://effbot.org/zone/python-with-statement.htm

import sys  fIn = 'symbolsIn.csv' fOut = 'symbolsOut.csv'  try:    with open(fIn, 'r') as f:       file_content = f.read()       print "read file " + fIn    if not file_content:       print "no data in file " + fIn       file_content = "name,phone,address\n"    with open(fOut, 'w') as dest:       dest.write(file_content)       print "wrote file " + fOut except IOError as e:    print "I/O error({0}): {1}".format(e.errno, e.strerror) except: #handle other exceptions such as attribute errors    print "Unexpected error:", sys.exc_info()[0] print "done"