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For example:
int x[100];
void *p;
x[0] = 0x12345678;
x[1] = 0xfacecafe;
x[3] = 0xdeadbeef;
p = x;
((int *) p) ++ ;
printf("The value = 0x%08x", *(int*)p);
Compiling the above generates an lvalue required error on the line with the ++ operator.
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When a pointer is incremented, it actually increments by the number equal to the size of the data type for which it is a pointer. For Example: If an integer pointer that stores address 1000 is incremented, then it will increment by 2(size of an int) and the new address it will points to 1002.
Incrementing the Value of Pointer in an ArrayBecause a pointer points to another value (e.g., an address in memory), it is also useful for array processing. While we can indicate the bucket of an array by using its index, we can also use pointers. For example, the following array shows how the incrementing works.
The only things you can do with a function pointer are read its value, assign its value, or call the function that it points toward. You cannot increment or decrement the address stored in a function pointer or perform any other arithmetic operations.
In programming (Java, C, C++, JavaScript etc.), the increment operator ++ increases the value of a variable by 1. Similarly, the decrement operator -- decreases the value of a variable by 1. a = 5 ++a; // a becomes 6 a++; // a becomes 7 --a; // a becomes 6 a--; // a becomes 5.
The cast creates a temporary pointer of type int *. You can't increment a temporary as it doesn't denote a place to store the result.
In C and C++ standardese, (int *)p is an rvalue, which roughly means an expression that can only occur on the right-hand side of an assignment.
p on the other hand is an lvalue, which means it can validly appear on the left-hand side of an assignment. Only lvalues can be incremented.
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