What happens if a lambda is moved/destructed while it is running?

Question

Consider:

std::vector<std::function<void()>> vec;
something_unmovable m;
vec.push_back([&vec, m]() {
    vec.resize(100);
    // things with 'm'
});
vec[0]();

vec.resize(100) will probably cause a re-allocation of the vector, which means that the std::functions will be copied to a new location, and the old ones destroyed. Yet this happens while the old one is still running. This particular code runs because the lambda doesn't do anything, but I imagine this can easily result in undefined behavior.

So, what happens exactly? Is m still accessible from the vector? Or is it that the this pointer of the lambda is now invalid (points to freed memory), so nothing the lambda captures can be accessible, yet if it runs code that doesn't use anything it captures, it's not undefined behavior?

Also, is the case where the lambda is movable any different?