I'm familiar with yield to return a value thanks mostly to this question
but what does yield do when it is on the right side of an assignment?
@coroutine
def protocol(target=None):
while True:
c = (yield)
def coroutine(func):
def start(*args,**kwargs):
cr = func(*args,**kwargs)
cr.next()
return cr
return start
I came across this, on the code samples of this blog, while researching state machines and coroutines.
The yield
statement used in a function turns that function into a "generator" (a function that creates an iterator). The resulting iterator is normally resumed by calling next()
. However it is possible to send values to the function by calling the method send()
instead of next()
to resume it:
cr.send(1)
In your example this would assign the value 1
to c
each time.
cr.next()
is effectively equivalent to cr.send(None)
You can send values to the generator using the send
function.
If you execute:
p = protocol()
p.next() # advance to the yield statement, otherwise I can't call send
p.send(5)
then yield
will return 5, so inside the generator c
will be 5.
Also, if you call p.next()
, yield
will return None
.
You can find more information here.
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