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Looking through this C++ BigInt library and found the BigInt.cpp file. At the top there is a a comment at the top about compatibility:
This class was written for the g++ compiler and uses some of the g++ extensions (like "long double" and the ">?=" operator).
What does that >?= operator do? I can't find a reference to it anywhere else.
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The right shift operator ( >> ) returns the signed number represented by the result of performing a sign-extending shift of the binary representation of the first operand (evaluated as a two's complement bit string) to the right by the number of bits, modulo 32, specified in the second operand.
It means to perform a bitwise operation with the values on the left and right-hand side, and then assign the result to the variable on the left, so a bit of a short form.
It's a GCC extension that was removed in GCC version 4.2 and later.
The equivalent of a >?= b is a = max(a,b);
There is also a very similar operator a <?= b which means the same as a = min(a, b);.
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This page describes that >? is the 'maximum' operator, which returns the largest of its two numeric arguments. I'm guessing that the >?= combines this with assignment, presumably by assigning to the left-hand operand if the right-hand value is larger.
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