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What does the \? (backslash question mark) escape sequence mean?

I'm writing a regular expression in Objective-C.

The escape sequence \w is illegal and emits a warning, so the regular expression /\w/ must be written as @"\\w"; the escape sequence \? is valid, apparently, and doesn't emit a warning, so the regular expression /\?/ must be written as @"\\?" (i.e., the backslash must be escaped).

Question marks aren't invisible like \t or \n, so why is \? a valid escape sequence?

Edit: To clarify, I'm not asking about the quantifier, I'm asking about a string escape sequence. That is, this doesn't emit a warning:

NSString *valid = @"\?";

By contrast, this does emit a warning ("Unknown escape sequence '\w'"):

NSString *invalid = @"\w";
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thomasd Avatar asked Aug 09 '13 20:08

thomasd


1 Answers

It specifies a literal question mark. It is needed because of a little-known feature called trigraphs, where you can write a three-character sequence starting with question marks to substitute another character. If you have trigraphs enabled, in order to write "??" in a string, you need to write it as "?\?" in order to prevent the preprocessor from trying to read it as the beginning of a trigraph.

(If you're wondering "Why would anybody introduce a feature like this?": Some keyboards or character sets didn't include commonly used symbols like {. so they introduced trigraphs so you could write ??< instead.)

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Chuck Avatar answered Sep 28 '22 00:09

Chuck