I read that std::vector
should be contiguous. My understanding is, that its elements should be stored together, not spread out across the memory. I have simply accepted the fact and used this knowledge when for example using its data()
method to get the underlying contiguous piece of memory.
However, I came across a situation, where the vector's memory behaves in a strange way:
std::vector<int> numbers; std::vector<int*> ptr_numbers; for (int i = 0; i < 8; i++) { numbers.push_back(i); ptr_numbers.push_back(&numbers.back()); }
I expected this to give me a vector of some numbers and a vector of pointers to these numbers. However, when listing the contents of the ptr_numbers
pointers, there are different and seemingly random numbers, as though I am accessing wrong parts of memory.
I have tried to check the contents every step:
for (int i = 0; i < 8; i++) { numbers.push_back(i); ptr_numbers.push_back(&numbers.back()); for (auto ptr_number : ptr_numbers) std::cout << *ptr_number << std::endl; std::cout << std::endl; }
The result looks roughly like this:
1 some random number 2 some random number some random number 3
So it seems as though when I push_back()
to the numbers
vector, its older elements change their location.
So what does it exactly mean, that std::vector
is a contiguous container and why do its elements move? Does it maybe store them together, but moves them all together, when more space is needed?
Edit: Is std::vector
contiguous only since C++17? (Just to keep the comments on my previous claim relevant to future readers.)
Vectors are assigned memory in blocks of contiguous locations. When the memory allocated for the vector falls short of storing new elements, a new memory block is allocated to vector and all elements are copied from the old location to the new location.
The elements of a vector are stored in a dynamically allocated block of memory; otherwise, the capacity of the vector could not increase. The vector object just holds a pointer to that block.
Yes, the elements of a std::vector are guaranteed to be contiguous.
To model computer memory, we use a new kind of data structure called a vector. Abstractly, a vector is a compound data object whose individual elements can be accessed by means of an integer index in an amount of time that is independent of the index.
It roughly looks like this (excuse my MS Paint masterpiece):
The std::vector
instance you have on the stack is a small object containing a pointer to a heap-allocated buffer, plus some extra variables to keep track of the size and and capacity of the vector.
So it seems as though when I
push_back()
to thenumbers
vector, its older elements change their location.
The heap-allocated buffer has a fixed capacity. When you reach the end of the buffer, a new buffer will be allocated somewhere else on the heap and all the previous elements will be moved into the new one. Their addresses will therefore change.
Does it maybe store them together, but moves them all together, when more space is needed?
Roughly, yes. Iterator and address stability of elements is guaranteed with std::vector
only if no reallocation takes place.
I am aware, that
std::vector
is a contiguous container only since C++17
The memory layout of std::vector
hasn't changed since its first appearance in the Standard. ContiguousContainer
is just a "concept" that was added to differentiate contiguous containers from others at compile-time.
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