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What does retag parameter in s/multi-spec mean?

Can you explain with examples how does retag parameter impacts multi-spec creation? I find multi-spec documentation hard to digest.

like image 750
OlegTheCat Avatar asked Jul 29 '17 22:07

OlegTheCat


1 Answers

From the docstring:

retag is used during generation to retag generated values with matching tags. retag can either be a keyword, at which key the dispatch-tag will be assoc'ed, or a fn of generated value and dispatch-tag that should return an appropriately retagged value.

If retag is a keyword (as in the spec guide example), multi-spec internally creates a function here which is used in the generator implementation function. For example, these two multi-spec declarations are functionally equivalent:

(s/def :event/event (s/multi-spec event-type :event/type))
(s/def :event/event (s/multi-spec event-type
                                  (fn [genv tag]
                                    (assoc genv :event/type tag))))

Passing a retag function wouldn't seem like a very useful option given the guide's example, but is more useful when using multi-spec for non-maps. For example, if you wanted to use multi-spec with s/cat e.g. to spec function args:

(defmulti foo first)
(defmethod foo :so/one [_]
  (s/cat :typ #{:so/one} :num number?))
(defmethod foo :so/range [_]
  (s/cat :typ #{:so/range} :lo number? :hi number?))

foo takes either two or three args, depending on the first arg. If we try to multi-spec this naively using the s/cat keyword/tag, it won't work:

(s/def :so/foo (s/multi-spec foo :typ))
(sgen/sample (s/gen :so/foo))
;; ClassCastException clojure.lang.LazySeq cannot be cast to clojure.lang.Associative

This is where being able to pass a retag function is useful:

(s/def :so/foo (s/multi-spec foo (fn [genv _tag] genv)))
(sgen/sample (s/gen :so/foo))
;=>
;((:so/one -0.5)
; (:so/one -0.5)
; (:so/range -1 -2.0)
; (:so/one -1)
; (:so/one 2.0)
; (:so/range 1.875 -4)
; (:so/one -1)
; (:so/one 2.0)
; (:so/range 0 3)
; (:so/one 0.8125))
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Taylor Wood Avatar answered Oct 27 '22 14:10

Taylor Wood