What does `*` mean in a C `typedef struct` declaration?

Question

I'm looking at a C struct with some syntax I've never seen before. The structure looks like this:

typedef struct structExample {
   int member1;
   int member2
} * structNAME;

I know that normally with a structure of:

typedef struct structExample {
   int member1;
   int member2
} structNAME;

I could refer to a member of the second struct definition by saying:

structNAME* tempStruct = malloc(sizeof(structNAME));
// (intitialize members)
tempstruct->member1;

What does that extra * in the the first struct definition do, and how would I reference members of the first struct definition?

Answer 1

It means the defined type is a pointer type. This is an equivalent way to declare the type:

struct structExample {
    int member1;
    int member2;
};
typedef struct structExample * structNAME;

You would use it like this:

structNAME mystruct = malloc (sizeof (struct structExample));
mystruct->member1 = 42;

Answer 2

The typedef makes these two statements the same

struct structExample *myStruct;
structName myStruct;

It makes structName stand for a pointer to struct structExample

As an opinion, I dislike this coding style, because it makes it harder to know whether a variable is a pointer or not. It helps if you have

typedef struct structExample * structExampleRef;

to give a hint that it is a pointer to struct structExample;