What does this do?
const wchar_t *s = L"test";
If wchar_t is two bytes on my machine, then why should we tell the compiler that the string should be treated in a way that each element is long i.e, four bytes in size?
S is Sport mode. It will make the throttle sharper and keep the rpms higher. Imagine a normal auto holding gears longer before shifts. L is for low gear. It would be used when going down a steep grade.
L – Low Gear: This position is typically used for towing or driving on steep inclines. S - Sport: Puts the car into a lower gear so you can have more power and control when accelerating. M - Manual: This position allows you to shift gears manually, giving you more control over your car's speed.
Yes, you can shift from D to L while moving in an automatic transmission car. Today's transmission are electronic. There are rev limiters for shifting to lower gears. The transmission simply won't shift to a lower gear above a certain RPM for each gear.
The L
means that string is a string of wchar_t
characters, rather than the normal string of char
characters. I'm not sure where you got the bit about four bytes from.
From the spec section 6.4.5 String literals, paragraph 2:
A character string literal is a sequence of zero or more multibyte characters enclosed in double-quotes, as in
"xyz"
. A wide string literal is the same, except prefixed by the letterL
.
And an excerpt from paragraph 5:
For character string literals, the array elements have type
char
, and are initialized with the individual bytes of the multibyte character sequence; for wide string literals, the array elements have typewchar_t
, and are initialized with the sequence of wide characters corresponding to the multibyte character sequence, as defined by thembstowcs
function with an implementation-defined current locale.
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