The keyof type operatorThe keyof operator takes an object type and produces a string or numeric literal union of its keys. The following type P is the same type as “x” | “y”: type Point = { x : number; y : number }; type P = keyof Point ; type P = keyof Point.
TypeScript adds a typeof operator you can use in a type context to refer to the type of a variable or property: let s = "hello"; let n : typeof s ; let n: string. This isn't very useful for basic types, but combined with other type operators, you can use typeof to conveniently express many patterns.
TypeScript comes with some built-in type guards: typeof and instanceof . They're very useful, but have limited scope. For example, typeof can only be used to check string , number , bigint , function , boolean , symbol , object , and undefined types.
To understand the keyof typeof
usage in TypeScript, first you need to understand what are literal types and union of literal types. So, I'll explain these concepts first and then explain keyof
and typeof
individually in detail. After that, I'll come back to enum
to answer what is asked in the question. It's a long answer but examples are easy to understand.
Literal types in TypeScript are more specific types of string
, number
or boolean
. For example, "Hello World"
is a string
, but a string
is not "Hello World"
. "Hello World"
is a more specific type of type string
, so it is a literal type.
A literal type can be declared as following:
type Greeting = "Hello"
This means that the object of type Greeting
can have only a string
value "Hello"
and no other string
value or any other value of any other type as shown in the following code:
let greeting: Greeting
greeting = "Hello" // OK
greeting = "Hi" // Error: Type '"Hi"' is not assignable to type '"Hello"'
Literal types are not useful on their own, however when combined with union types, type aliases and type guards they become powerful.
Following is an example of union of literal types:
type Greeting = "Hello" | "Hi" | "Welcome"
Now the object of type Greeting
can have the value either "Hello"
, "Hi"
or "Welcome"
.
let greeting: Greeting
greeting = "Hello" // OK
greeting = "Hi" // OK
greeting = "Welcome" // OK
greeting = "GoodEvening" // Error: Type '"GoodEvening"' is not assignable to type 'Greeting'
keyof
onlykeyof
of some type T
gives you a new type that is a union of literal types and these literal types are the names of the properties of T
. The resulting type is a subtype of string.
For example, consider the following interface
:
interface Person {
name: string
age: number
location: string
}
Using the keyof
operator on the type Person
will give you a new type as shown in the following code:
type SomeNewType = keyof Person
This SomeNewType
is a union of literal types ("name" | "age" | "location"
) that is made from the properties of type Person
.
Now you can create objects of type SomeNewType
:
let newTypeObject: SomeNewType
newTypeObject = "name" // OK
newTypeObject = "age" // OK
newTypeObject = "location" // OK
newTypeObject = "anyOtherValue" // Error...
keyof typeof
together on an objectAs you might already know, the typeof
operator gives you the type of an object.
In the above example of Person
interface, we already knew the type, so we just had to use the keyof
operator on type Person
.
But what to do when we don't know the type of an object or we just have a value and not a type of that value like the following?
const bmw = { name: "BMW", power: "1000hp" }
This is where we use keyof typeof
together.
The typeof bmw
gives you the type: { name: string, power: string }
And then keyof
operator gives you the literal type union as shown in the following code:
type CarLiteralType = keyof typeof bmw
let carPropertyLiteral: CarLiteralType
carPropertyLiteral = "name" // OK
carPropertyLiteral = "power" // OK
carPropertyLiteral = "anyOther" // Error...
keyof typeof
on an enum
In TypeScript, enums are used as types at compile-time to achieve type-safety for the constants but they are treated as objects at runtime. This is because, they are converted to plain objects once the TypeScript code is compiled to JavaScript. So, the explanation of the objects above is applicable here too. The example given by OP in the question is:
enum ColorsEnum {
white = '#ffffff',
black = '#000000',
}
Here ColorsEnum
exists as an object at runtime, not as a type. So, we need to invoke keyof typeof
operators together as shown in the following code:
type Colors = keyof typeof ColorsEnum
let colorLiteral: Colors
colorLiteral = "white" // OK
colorLiteral = "black" // OK
colorLiteral = "red" // Error...
That's it! Hope that helps.
keyof
takes an object type and returns a type that accepts any of the object's keys.
type Point = { x: number; y: number };
type P = keyof Point; // type '"x" || "y"'
const coordinate: P = 'z' // Type '"z"' is not assignable to type '"x" | "y"'.
typeof
behaves differently when called on javascript objects, to when it is called on typescript types.
"undefined", "object", "boolean", "number", "bigint", "string", "symbol", "function"
type Language = 'EN' | 'ES';
const userLanguage: Language = 'EN';
const preferences = { language: userLanguage, theme: 'light' };
console.log(typeof preferences); // "object"
type Preferences = typeof preferences; // type '{language: 'EN''; theme: string; }'
Because the second typeof preferences
is in a type expression it is actually TypeScript's own typeof
that get called, and not javascript's.
Because keyof
is a TypeScript concept we will be calling TypeScript's verion of typeof
.
keyof typeof
will infer the type of a javascript object and return a type that is the union of its keys. Because it can infer the exact value of the keys it can return a union of their literal types instead of just returning "string".
type PreferenceKeys = keyof typeof preferences; // type '"language" | "theme"'
An enum
creates an instantiated object
. With typeof
we get the auto generated type of this enum
.
Now we can get all indices with keyof
to make sure Colors
can only contain one of them.
Common misconception about TypeScript
TypeScript is often described as a type layer on top of JavaScript runtime. As if types and values lived on separate planes. However, in TypeScript, some things are types and values at the same time.
This is true for:
When can you use keyof
?
The keyof
keyword only works on the type level. You cannot apply it to a JavaScript value.
When do you need keyof typeof
?
When you're dealing with something that is a type and a value at the same time (like a class or an enum), but you're interested specifically in what the type of that value is.
The simplest example:
const foo = { bar: 42 }; // foo is a value
type Foo = typeof foo; // Foo is the type of foo
type KeyOfFoo = keyof Foo; // "keyof Foo" is the same as "keyof typeof foo", which is "bar"
In general, when you see this:
type A = keyof typeof B;
the typeof B
part tells TypeScript to look at the type of B. You can think of it as casting B to its type. Sort of like casting a two-dimensional object to a one-dimensional space.
Since typeof B
is a type, not a value, we can now use keyof
on it.
Example
Classes are types and values. You can call them, but you can also use keyof
on them.
declare class Foo {
static staticProperty: string;
dynamicProperty: string;
}
type Constructor = typeof Foo;
type Instance = Foo;
type A = keyof Constructor; // "prototype" | "staticProperty"
type B = keyof Instance; // "dynamicProperty"
By using typeof
together with keyof
, we can toggle between using keyof
against the instance type and the constructor type.
For finding the type of any values we use typeof operation. For eg
const user = {
getPersonalInfo(){},
getLocation(){}
}
Here user is a value so here typeof operator comes in handy
type userType = typeof user
Here userType gives type information that user is an object which have two properties getPersonalInfo and getLocation and both are functions return void
Now if you want to find the keys of user you can use keyof
type userKeys = keyof userType
which says userKeys= 'getPersonalInfo'| 'getLocation'
Beware if you try to get user's key like
type userKeys = keyof user
you will get an error 'user' refers to a value, but is being used as a type here. Did you mean 'typeof user'?
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