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What does it mean for a binary to be 'munched' after it is compiled?

Tags:

c++

vxworks

The title pretty much says it. This is w/regard to VxWorks; unfortunately, the documentation more or less says that it happens but not why or what purpose it serves.

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Brian Vandenberg Avatar asked Dec 28 '25 03:12

Brian Vandenberg


1 Answers

It's been a few years since I had to deal with vxworks "munching", but what it does is create the C++ static constructor call table. It apparently isn't needed in the current (6.8+) versions that we're using now. What I recall was from 5.4, I think.

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Richard Pennington Avatar answered Dec 30 '25 16:12

Richard Pennington



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