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This is the snippet:
String myTime = someTime / 1e9d + ",";
someTime is derived by using System.nanoTime(). What does 1e9d do here?
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1e9 simply means (1) * (10^9) Typecast 1e9 to int since by default is is double => (int)1e9.
E10 means move the decimal to the right 10 places.
The e (or E ) means "times 10-to-the", so 1e9 is "one times ten to the ninth power", and 1e-9 means "one times ten to the negative ninth power".
1e9 means 10^9 2d means 2 as double
e.g.
1e9 => 1.0E910e9 => 1.0E10See also the Floating-Point Literals section of The Java™ Tutorials.
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The suffix d denotes a double number. If the number wasn't treated as a floating point number, then the division would be considered an integer division, returning an integer (e.g. 3/2=1).
1e9 is simply 10^9. The conversion seems to be from nanoseconds to seconds.
--EDIT--
Ingo correctly points out that 10e9 is already evaluated by java to a double (see this part of the spec for details). Therefore the 'd' isn't needed in this case.
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