In this answer, the following code is given (C++11):
template <typename T, size_t N>
constexpr size_t size_of(T (&)[N]) {
return N;
}
What does the (&)
mean in this context? This sort of thing is exceptionally difficult to search for.
Speaking of the meaning of the song, Vegard characterizes it as coming from "a genuine wonder of what the fox says, because we didn't know". Although interpreted by some commentators as a reference to the furry fandom, the brothers have stated they did not know about its existence when producing "The Fox".
One of the most common fox vocalizations is a raspy bark. Scientists believe foxes use this barking sound to identify themselves and communicate with other foxes. Another eerie fox vocalization is a type of high-pitched howl that's almost like a scream.
Ask Google Assistant to name a song On your phone, touch and hold the Home button or say "Hey Google." Ask "What's this song?" Play a song or hum, whistle, or sing the melody of a song. Hum, whistle, or sing: Google Assistant will identify potential matches for the song.
It's shorthand for something like this:
template <typename T, size_t N>
constexpr size_t size_of(T (&anonymous_variable)[N]) {
return N;
}
In the function, you don't actually need the name of the variable, just the template deduction on N
- so we can simply choose to omit it. The parentheses are syntactically necessary in order to pass the array in by reference - you can't pass in an array by value.
This is passing an array as a parameter by reference:
template <typename T, size_t N>
constexpr size_t size_of(T (&)[N]) {
return N;
}
As you cannot pass an array like this:
template <typename T, size_t N>
constexpr size_t size_of(T[N]) {
return N;
}
If the array was given a name, it would look like:
template <typename T, size_t N>
constexpr size_t size_of(T (&arrayname)[N]) {
return N;
}
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