In a dictionary like this:
Dictionary<string, string> openWith = new Dictionary<string, string>(); openWith.Add("txt", "notepad.exe"); openWith.Add("bmp", "paint.exe"); openWith.Add("dib", "paint.exe"); openWith.Add("rtf", "wordpad.exe"); Console.WriteLine("For key = \"rtf\", value = {0}.", openWith["rtf"]);
The output is:
For Key = "rtf" value = wordpad.exe
What does the {0}
mean?
It's the "end" of a string. A null character.
“\0” is the null termination character. It is used to mark the end of a string. Without it, the computer has no way to know how long a group of characters (string) goes. In C/C++ it looks for the Null Character to find the end of a string.
C++ uses a marker, the null character, denoted by '\0', to indicate the end of the string. Note: A string is different from an array of characters in that the null character is at the end of the string.
Strings are actually one-dimensional array of characters terminated by a null character '\0'. Thus a null-terminated string contains the characters that comprise the string followed by a null.
You are printing a formatted string. The {0} means to insert the first parameter following the format string; in this case the value associated with the key "rtf".
For String.Format, which is similar, if you had something like
// Format string {0} {1} String.Format("This {0}. The value is {1}.", "is a test", 42 )
you'd create a string "This is a test. The value is 42".
You can also use expressions, and print values out multiple times:
// Format string {0} {1} {2} String.Format("Fib: {0}, {0}, {1}, {2}", 1, 1+1, 1+2)
yielding "Fib: 1, 1, 2, 3"
See more at http://msdn.microsoft.com/en-us/library/txafckwd.aspx, which talks about composite formatting.
It's a placeholder in the string.
For example,
string b = "world."; Console.WriteLine("Hello {0}", b);
would produce this output:
Hello world.
Also, you can have as many placeholders as you wish. This also works on String.Format
:
string b = "world."; string a = String.Format("Hello {0}", b); Console.WriteLine(a);
And you would still get the very same output.
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