Here are two related questions but they are not duplicates of mine as the first one has a solution specific to the data set and the second one involves a failure of glm
when start
is supplied alongside an offset
.
https://stackoverflow.com/questions/31342637/error-please-supply-starting-valueshttps://stackoverflow.com/questions/8212063/r-glm-starting-values-not-accepted-log-link
I have the following dataset:
library(data.table)
df <- data.frame(names = factor(1:10))
set.seed(0)
df$probs <- c(0, 0, runif(8, 0, 1))
df$response = lapply(df$probs, function(i){
rbinom(50, 1, i)
})
dt <- data.table(df)
dt <- dt[, list(response = unlist(response)), by = c('names', 'probs')]
such that dt
is:
> dt
names probs response
1: 1 0.0000000 0
2: 1 0.0000000 0
3: 1 0.0000000 0
4: 1 0.0000000 0
5: 1 0.0000000 0
---
496: 10 0.9446753 0
497: 10 0.9446753 1
498: 10 0.9446753 1
499: 10 0.9446753 1
500: 10 0.9446753 1
I am trying to fit a logistic regression model with the identity link, using lm2 <- glm(data = dt, formula = response ~ probs, family = binomial(link='identity'))
.
This gives an error:
Error: no valid set of coefficients has been found: please supply starting values
I tried fixing it by supplying a start
argument, but then I get another error.
> lm2 <- glm(data = dt, formula = response ~ probs, family = binomial(link='identity'), start = c(0, 1))
Error: cannot find valid starting values: please specify some
At this point these errors make no sense to me and I have no idea what to do.
EDIT: @iraserd has thrown some more light on this problem. Using start = c(0.5, 0.5)
, I get:
> lm2 <- glm(data = dt, formula = response ~ probs, family = binomial(link='identity'), start = c(0.5, 0.5))
There were 25 warnings (use warnings() to see them)
> warnings()
Warning messages:
1: step size truncated: out of bounds
2: step size truncated: out of bounds
3: step size truncated: out of bounds
4: step size truncated: out of bounds
5: step size truncated: out of bounds
6: step size truncated: out of bounds
7: step size truncated: out of bounds
8: step size truncated: out of bounds
9: step size truncated: out of bounds
10: step size truncated: out of bounds
11: step size truncated: out of bounds
12: step size truncated: out of bounds
13: step size truncated: out of bounds
14: step size truncated: out of bounds
15: step size truncated: out of bounds
16: step size truncated: out of bounds
17: step size truncated: out of bounds
18: step size truncated: out of bounds
19: step size truncated: out of bounds
20: step size truncated: out of bounds
21: step size truncated: out of bounds
22: step size truncated: out of bounds
23: step size truncated: out of bounds
24: step size truncated: out of bounds
25: glm.fit: algorithm stopped at boundary value
and
> summary(lm2)
Call:
glm(formula = response ~ probs, family = binomial(link = "identity"),
data = dt, start = c(0.5, 0.5))
Deviance Residuals:
Min 1Q Median 3Q Max
-2.4023 -0.6710 0.3389 0.4641 1.7897
Coefficients:
Estimate Std. Error z value Pr(>|z|)
(Intercept) 1.486e-08 1.752e-06 0.008 0.993
probs 9.995e-01 2.068e-03 483.372 <2e-16 ***
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
(Dispersion parameter for binomial family taken to be 1)
Null deviance: 69312 on 49999 degrees of freedom
Residual deviance: 35984 on 49998 degrees of freedom
AIC: 35988
Number of Fisher Scoring iterations: 24
I highly suspect this has something to do with the fact that some of the responses are generated with true probability zero which causes problems as the coefficient of probs
approaches 1.
There are two places in the fit.glm
code where it terminates with the error no valid set of coefficients has been found: please supply starting values
. In one case, when some calculated deviance becomes infinite, the other case seems to occur when invalid etastart
and mustart
options are provided.
See also the answer to, which elaborates in detail: How do I use a custom link function in glm?
As you try to make a regression on probabilities (values between 0 and 1), I guess you need to specify starting values unequal to 0 or 1:
lm2 <- glm(data = dt, formula = response ~ probs, family = binomial(link='identity'), start=c(0.5,0.5))
This throws a lot of warnings and terminates with an overflow, probably because of the artificial nature of the example.
Changing the formula to use the logit link (as you want a logistic regression according to your question) gets rid of the warnings (and does not need starting parameters):
lm2 <- glm(data = dt, formula = response ~ probs, family = binomial(link='logit')
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