The code that is causing problems looks like a normal xnor operation as you can see below:
S(1) <= L(16) xnor L(26);
This line causes the following error:
ncvhdl_p: *E,EXPSMI (HDL/aes_sbox_enc_depth16.vhd,169|14): expecting a semicolon (';') [9.5.1].
ncvhdl_p: *F,MAXERR: maximum error count reached (1).
TOOL: ncvhdl 10.20-s075: Exiting on Feb 14, 2012 at 12:56:05 GMT (total: 00:00:01)
Anyone an idea what is going wrong here, the semicolon is clearly there. Is it possible that VHDL does not support xnor, if so, how do I have to rewrite it?
Many thanks!
I believe that xnor
is defined for bits and booleans, but not std_logic. I think it actually depends on which version of VHDL (e.g. 98 / 2002 / 2008) you're using. It's certainly commented out of some versions of the std_logic_1164.vhd
files I've seen.
How about just inverting an xor
?
S(1) <= not (L(16) xor L(26));
To elaborate on Paul's Answer.
This can be verified by looking at Section 7.1 of the Language Spec.
For Year 1987:
expression ::=
relation { and relation }
| relation { or relation }
| relation { xor relation }
| relation [ nand relation ]
| relation [ nor relation ]
For Year 2002:
expression ::=
relation { and relation }
| relation { or relation }
| relation { xor relation }
| relation [ nand relation ]
| relation [ nor relation ]
| relation { xnor relation }
If your tool supports 2002 (or 2008), then it would also need to define the operator in std_logic_1164, but that would be relatively likely.
What is most likely, is that your tool is only supporting IEEE-1076-1987. You would then want to write an xnor as:
not(L(16) xor L(26));
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