Way to quickly shuffle the numbers 1 through 4?

Question

Looking to shuffle four variables (trying to change the order they appear in on a multiple choice list).

I've been poking around for a while but I can't quite get my head around the logic, and looking up random shuffles in past questions gives super-detailed algorithms that are beyond my newbie skills (and the needs of this program I'm trying to write, I'd just like to make a multiple-choice image picker).

Ideally I'd like something that follows this pseudocode:

// int Answer1 = Random(min1 max4)

// int Answer2 = Random(min1 max4)

// int Answer3 = Random(min1 max4)

// int Answer4 = Random(min1 max4)

// If Answer 1 equals ANY of the other three, re-randomize Answer1 and loop.

// Loop through this cycle for all answers.

I'd post my current regular code, but frankly, it's garbage. :( This seems like a simple enough problem but I just can't get it right.

Thanks in advance!

Answer 1

Shuffling - http://www.codinghorror.com/blog/archives/001008.html

Though, don't use a guid, use a random number:

//create only once, please
static readonly Random random = new Random();

and then:

var numbers = Enumerable.Range(1, 4);
var shuffle = numbers.OrderBy(a => random.NextDouble());

Answer 2

I like this extension method:

static class IListExtensions {
    public static void Shuffle<T>(this IList<T> list, Random rg) {
        for (int i = list.Count; i > 1; i--) {
            int k = rg.Next(i);
            T temp = list[k];
            list[k] = list[i - 1];
            list[i - 1] = temp;
        }
    }
}

Then:

Random rg = new Random();
List<int> list = Enumerable.Range(1, 4).ToList();
list.Shuffle(rg);

Now list is a shuffling of {1, 2, 3, 4}.

The algorithm that I used here is the Fisher-Yates shuffle.