Way to pass multiple parameters to a function in python

Question

I have written a python script which calls a function. This function takes 7 list as parameters inside the function, something like this:

def WorkDetails(link, AllcurrValFound_bse, AllyearlyHLFound_bse, 
                AlldaysHLFound_bse, AllvolumeFound_bse, 
                AllprevCloseFound_bse, AllchangePercentFound_bse, 
                AllmarketCapFound_bse):

where all the arguments except link are lists. But this makes my code looks pretty ugly. I pass these lists to this function because the function appends few values in all of these lists. How can I do it in more readable way for other users?

Answer 1

test function:

You can use multiple arguments represented by *args and multiple keywords represented by **kwargs and passing to a function:

def test(*args, **kwargs):
    print('arguments are:')
    for i in args:
        print(i)

    print('\nkeywords are:')
    for j in kwargs:
        print(j)

Example:

Then use any type of data as arguments and as many parameters as keywords for the function. The function will automatically detect them and separate them to arguments and keywords:

a1 = "Bob"      #string
a2 = [1,2,3]    #list
a3 = {'a': 222, #dictionary
      'b': 333,
      'c': 444}

test(a1, a2, a3, param1=True, param2=12, param3=None)

Output:

arguments are:
Bob
[1, 2, 3]
{'a': 222, 'c': 444, 'b': 333}

keywords are:
param3
param2
param1