I'm new to PHP, and I'm trying to build a script. When I load the script, I get the following error:
Warning: opendir(http://www.hetweerinboskamp.nl/voorpagina/movies) [function.opendir]: failed to open dir: not implemented
<?php
$hal ='';
$dir ='http://www.hetweerinboskamp.nl/voorpagina/movies';
if ($handle = opendir($dir)) {
// Loop the folders
while (false !== ($file = readdir($handle))) {
if(strlen($file) > 4) {
$rawd = parsename($file);
$hal.= 'new Date('.substr($rawd,0,4).', '.substr($rawd,4,2).'-1, '.substr($rawd,6,2).'),';
//$hal.= $rawd.',';
}
closedir($handle);
}
opendir()
is used to open a local directory and since PHP 5.0.0 on an ftp directory.
If your PHP code runs on www.hetweerinboskamp.nl then /voorpagina/movies
is actually a local directory and you can do this:
$dir ='<wwwroot>/voorpagina/movies';
if ($handle = opendir($dir)) {
where wwwroot
is the root of the filesystem as seen by your php code.
If you're trying to download content from another website, try e.g. file_get_contents()
. Note that if the remote server lists the content of a directory the listing is in fact an HTML page generated on the fly by the server. You may find yourself needing to parse that page. A better approach is to check whether the server offers some sort of API where it sends back the content in a standardized form, e.g. in JSON format.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With