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Waiting for an event in Java - how hard is it?

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I have a thread that updates it's state from time to time and I want a second thread to be able to wait for the first thread to be done. Something like this:

Thread 1:     while(true) {         ...do something...         foo.notifyAll()         ...wait for some condition that might never happen...         ...     }  Thread 2:     ...     foo.wait();     ... 

Now this looks nice and all unless Thread 1's notifyAll() runs before Thread 2's wait(), in which case Thread 2 waits until Thread 1 notifies again (which might never happen).

My possible solutions:

a) I could use a CountDownLatch or a Future, but both have the problem that they inherently only run once. That is, in Thread 1's while loop, I would need to create a new foo to wait for each time and Thread 2 would need to ask which foo to wait for. I have a bad feeling about simply writing

while(true) {    foo = new FutureTask();     ...    foo.set(...);    ...wait for a condition that might never be set...    ... } 

as I fear that at foo = new FutureTask(), what happens when someone waited for the old foo (for "some reason", set was not called, e.g. a bug in the exception handling)?

b) Or I could use a semaphore:

class Event {    Semaphore sem;    Event() { sem = new Semaphore(1); sem . }    void signal() { sem.release(); }    void reset() { sem.acquire(1); }    void wait() { if (sem.tryAcquire(1)) { sem.release(); } } } 

But I fear that there is some race condition, if multiple threads are wait()ing for it while another one signal()s and reset()s.

Question:

Is there nothing in the Java API that resembles the Windows Event behaviour? Or, if you despise Windows, something like golang's WaitGroup (i.e. a CountDownLatch that allows countUp())? Anything?

How to do it manually:

Thread 2 cannot simply wait because of spurious wakeup and in Java there is no way to know why Object.wait() returned. So I need a condition variable that stores whether the event is signalled or not. Thread 2:

synchronized(foo) {     while(!condition) {         foo.wait();     } } 

And Thread 1 of course sets condition to true in a synchronized block. Thanks to weekens for the hint!

Is there an existing class that wraps that behaviour?

Or do I need to copy and paste the code all over?

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Kosta Avatar asked Dec 19 '11 13:12

Kosta


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1 Answers

It is standard practice to change some state when performing notifyAll and to check some state when performing wait().

e.g.

boolean ready = false;  // thread 1 synchronized(lock) {     ready = true;     lock.notifyAll(); }   // thread 2 synchronized(lock) {     while(!ready)          lock.wait(); } 

With this approach, it doesn't matter if thread 1 or thread 2 acquires the lock first.

Some coding analysis tools will give you a warning if you use notify or wait without setting a value or checking a value.

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Peter Lawrey Avatar answered Oct 28 '22 11:10

Peter Lawrey