WaitAll vs WaitAny

Question

I am little bit confuse for WaitAll and WaitAny. I am trying to get exception but when i do WaitAll it return exception but When use WaitAny returns nothing.And necessary is that if any of task complete work done.Is their any Replacement of WaitAny(). WaitAll and WhenAll are different becuase i dont want let all task done. Like

try
{
    int i = 0;
    Task t1 = Task.Factory.StartNew(() =>
        {
            i = 2 * 4;
        });

    Task<int> t2 = Task.Factory.StartNew(() =>
        {
            int a = 0;
            int b = 100 / a;
            return 0;
        });

    Task[] tasks = new Task[] { t1, t2 };
    Task.WaitAny(tasks);
    //Task.WaitAll(tasks);// Working

}
catch (AggregateException ae)
{
    var message = ae.InnerException.Message;
    Console.WriteLine(message);
}
Console.ReadLine();

Answer 1

This is called Unobserved Exception, which basically means that exception in newly created threads in Task Parallel Library (TPL) ThreadPool, is not caught by the other thread or as stated in aforementioned link:

While unobserved exceptions will still cause the UnobservedTaskException event to be raised (not doing so would be a breaking change), the process will not crash by default. Rather, the exception will end up getting eaten after the event is raised, regardless of whether an event handler observes the exception.

This means that when using WaitAny(), if one of the tasks completes without any exception, exceptions in other tasks will not be caught.