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Variant visitor with different return types

Consider the following piece of code that uses boost::variant (but should apply perfectly well to std::variant as well).

#include <vector>
#include <boost/variant.hpp>

int main()
{
    boost::variant<std::vector<int>, std::vector<double> > vr 
        = std::vector<int>(5, 5);;

    // OK, no problem.
    boost::apply_visitor([](auto a) { std::cout << a[0] << "\n"; }, vr);

    // ERROR: return types must not differ.
    //boost::apply_visitor([](auto a) { return a.begin(); }, vr);
}

Here, we have variant that eats up standard vectors of different types (e.g., int and double in this example), and we'd like to have a visitor that returns objects of different types (in this case, iterators to the beginning of the underlying container). However, this won't compile as obviously std::vector<int>::iterator is not the same as std::vector<double>::iterator. Is there a neat way of essentially achieving this, possibly through an extra layer of indirection?

like image 957
Dan Tony Avatar asked May 12 '26 07:05

Dan Tony


1 Answers

You can return a different variant

#include <iostream>
#include <vector>
#include <boost/variant.hpp>

int main()
{
    boost::variant<std::vector<int>, std::vector<double> > vr 
        = std::vector<int>(5, 5);
    using iter_variant = boost::variant<std::vector<int>::iterator, std::vector<double>::iterator >;

    using value_variant = boost::variant<int, double>;

    // OK, no problem.
    boost::apply_visitor([](auto a) { std::cout << a[0] << "\n"; }, vr);

    // Also OK
    boost::apply_visitor([](auto a) -> iter_variant { return a.begin(); }, vr);

    // Also OK
    boost::apply_visitor([](auto a) -> value_variant { return a[0]; }, vr);
}

See it live

Given a generic lambda and a variant, you can get an appropriate return type.

template<typename Func, typename Variant>
struct visitor_result;

template<typename Func, typename ... Ts>
struct visitor_result<Func, boost::variant<Ts...>>
{
    using type = boost::variant<decltype(std::declval<Func>()(std::declval<Ts>()))...>;
};

template<typename Func, typename Variant>
using visitor_result_t = typename visitor_result<Func, Variant>::type;

template<typename Func, typename Variant>
visitor_result_t<Func, Variant> generic_visit(Func func, Variant variant)
{
    return boost::apply_visitor([&](auto a) -> visitor_result_t<Func, Variant> { return func(a); }, variant);
}

See it live

like image 130
Caleth Avatar answered May 13 '26 22:05

Caleth