Is something like the following possible in PHP?
$blah = 'foo1';
class foo2 extends $blah {
//...
}
class foo1 {
//...
}
This gives an error.
I want to dynamically set $blah so I can extend whatever class I want.
Edit: The reason for wanting to do this because I wanted to use a function out of another class in a related class. In the end it would have been something like:
Final extends foo1 extends foo2 extends foo3 extends foo4 extends parent { ... }
In the end I decided to instantiate the other class within the class and use it. Not the best options because they both you 2 of the same classes, but this won't be used that often, so it will work for now.
You're assuming here php executes top to bottom, but it doesn't quite work like that:
<?php
foo(); # works
function foo(){
print "bar";
}
<?php
foo(); #dies
if( $i == 1 )
{
function foo(){
print "bar";
}
}
<?php
$i = 1;
if( $i == 1 )
{
function foo(){
print "bar";
}
}
foo(); #works
Now, although you can conditionally create classes:
<?php
class A { }
class B { }
if( false ){
class C extends B {
public static function bar(){
print "baz";
}
}
}
C::bar(); # dies
You cant instantiate one at runtime from a variable:
<?php
class A { }
class B { }
$x = 'B';
if( false ){
class C extends $x {
public static function bar(){
print "baz";
}
}
}
C::bar();
---> Parse error: syntax error, unexpected T_VARIABLE, expecting T_STRING in /tmp/eg.php on line 7
There is a way to do it with Eval, but you really don't want to go there:
<?php
class A { }
class B { }
$x = 'B';
if( true ){
$code =<<<EOF
class C extends $x {
public static function bar(){
print "baz";
}
}
EOF;
eval( $code );
}
C::bar();
$o = new C;
if ( $o instanceof $x )
{
print "WIN!\n";
}
--->barWIN!
However, there is a more important question here:
Why the hell would you want to extend a different class at runtime
Anybody using your code will want to hold you down and whip you for that.
( Alternatively, if you're into whipping, do that eval trick )
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