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Validation for numeric data Javascript

Tags:

javascript

I'm writing a program in Javascript that separates even and odd numbers, puts them into an array, adds the sum of numbers, and finds the average.

I'm having an issue not allowing zeros not to count. Because its adding to the array, and when the user types in 6+6, sum is 12, average is calculating to 4 because of the extra 0 in the array.

Is there anyway to not allow the zeros to count? Here is what I have so far..

var evenarray = [];
    var oddarray = [];
    var avgEven = 0;
    var avgOdd = 0;
    var isValid;
    function numberFunction(){

        do  
        {

            var numbers = prompt("Please enter numbers. Enter empty string to exit.");

            if(numbers % 2 == 0)
            {   
                    evenarray.push(numbers);
                    var sumEven = 0;
                        for (var i=0; i < evenarray.length; i++)
                        {
                            sumEven = sumEven + Number(evenarray[i]);
                        }
                    var avgEven = sumEven/evenarray.length;
                    //alert("even");

            }
            if(numbers % 2 !== 0)
            {
                    oddarray.push(numbers);
                    var sumOdd = 0;
                        for (var i=0; i < oddarray.length; i++)
                        {
                            sumOdd = sumOdd + Number(oddarray[i]);
                        }
                    var avgOdd = sumOdd/oddarray.length;
                    //alert("odd");
            }

            //if(isNaN(numbers)){

                //alert("Only numeric data only");
                //}
        }

        while(numbers !== "");
like image 745
Atlas182 Avatar asked Nov 23 '25 16:11

Atlas182


1 Answers

Just do nothing when the number is actually 0:

if (numbers == 0)
{
}
else if(numbers % 2 == 0)
{   
  evenarray.push(numbers);
  var sumEven = 0;
  for (var i=0; i < evenarray.length; i++)
  {
    sumEven = sumEven + Number(evenarray[i]);
  }
  var avgEven = sumEven/evenarray.length;
}
else  // only odds remain
{
  oddarray.push(numbers);
  var sumOdd = 0;
  for (var i=0; i < oddarray.length; i++)
  {
    sumOdd = sumOdd + Number(oddarray[i]);
  }
  var avgOdd = sumOdd/oddarray.length;
}
like image 151
Paul Roub Avatar answered Nov 25 '25 10:11

Paul Roub



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