There is a code snippet in the swift book provided by Apple. I typed it in xcode playground but it shows "Operator is not a known binary operator" and "Use of unresolved identifier" errors. The code is:
According to the book, ".." operator can be used with for loop to make a range that omits its upper value. But it displays error. Changing ".." to "..." operator seems to fix the error. But why does not ".." work?
The continue statement can be used in both while and for loops.
Loops are control structures used to repeat a given section of code a certain number of times or until a particular condition is met. Visual Basic has three main types of loops: for.. next loops, do loops and while loops.
A: Syntax of for loop in c++ Language is for(initialization;condition;increment/decrement) Option (A)… Q: Q1) True/False questions: Write T for true andF for false statement.
You can put a for loop inside a while, or a while inside a for, or a for inside a for, or a while inside a while. Or you can put a loop inside a loop inside a loop. You can go as far as you want.
You have an out of date version of the swift book.
Here you go. The current version of the half-closed range is 0..<3
not 0..3
https://developer.apple.com/library/ios/documentation/swift/conceptual/Swift_Programming_Language/BasicOperators.html
Things are now different in Swift 2. Here's how to do it now in Xcode 7 (the original question shows highly in a google search for this particular problem):
for i in 1 ..< Process.argc {
let index = Int(i);
if let arg = String.fromCString(Process.unsafeArgv[index]) {
switch arg {
case "-whatever":
// do something
default:
break
}
}
}
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