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Using the values of a previous "row" in a pandas series

I have a CSV that looks like this (and when brought into a pandas Dataframe with read_csv(), it looks the same).

enter image description here

I want to update the values in column ad_requests according to the following logic:

For a given row, if ad_requests has a value, leave it alone. Else, give it a value of the previous row's value for ad_requests minus the previous row's value for impressions. So in the first example, we would like to end up with:

enter image description here

I get partially there:

df["ad_requests"] = [i if not pd.isnull(i) else ??? for i in df["ad_requests"]]

And this is where I get stuck. After the else, I want to "go back" and access the previous "row", though I know that this is not how pandas is meant to be used. Another thing to note that is the rows will always be grouped in threes, by column ad_tag_name. If I pd.groupby["ad_tag_name"], I can then turn this into a list and start slicing and indexing, but again, I think there must be a better way to do this in pandas (as there is many things).

Python: 2.7.10

Pandas: 0.18.0

like image 892
Pyderman Avatar asked Oct 18 '22 22:10

Pyderman


1 Answers

You'll want to do something like this:

pd.options.mode.chained_assignment = None #suppresses "SettingWithCopyWarning"
for index, elem in enumerate(df['ad_requests']):
    if pd.isnull(elem):
        df['ad_requests'][index]=df['ad_requests'][index-1]-df['impressions'][index-1]

The warning comes from the fact that we're changing the values of a view of a dataframe, which affects the original dataframe. That is what we wish to do, however, so it doesn't really concern us.

(Python 2.7.12 and Pandas 0.19.0)

EDIT:

Changing the last line of code from

df['ad_requests'][index]=df['ad_requests'][index-1]-df['impressions'][index-1]

to

df.at[index,'ad_requests']=df.at[index-1,'ad_requests']-df.at[index-1,'impressions']

removes the need to suppress any warnings:

for index, elem in enumerate(df['ad_requests']):
    if pd.isnull(elem):
        df.at[index,'ad_requests']=df.at[index-1,'ad_requests']-df.at[index-1,'impressions']
like image 88
Rojan Avatar answered Oct 21 '22 02:10

Rojan