Consider the following code snippet. It flags a syntax error at the break statement.
digits = list(str(102))
dummy = list(str(102/2))
for j in digits:
dummy.remove(j) if j in dummy else break
How do I fix this?(I want to still use the ternary operator)
Similarly the ternary operator in python is used to return a value based on the result of a binary condition. It takes binary value(condition) as an input, so it looks similar to an “if-else” condition block. However, it also returns a value so behaving similar to a function.
The ternary operator is a way of writing conditional statements in Python. As the name ternary suggests, this Python operator consists of three operands. The ternary operator can be thought of as a simplified, one-line version of the if-else statement to test a condition.
The conditional (ternary) operator is the only JavaScript operator that takes three operands: a condition followed by a question mark ( ? ), then an expression to execute if the condition is truthy followed by a colon ( : ), and finally the expression to execute if the condition is falsy.
Ternary operators are also known as conditional expressions are operators that evaluate something based on a condition being true or false. It was added to Python in version 2.5. It simply allows testing a condition in a single line replacing the multiline if-else making the code compact.
Edit:
(see my conversation with Stefan Pochmann in the comments)
Ternary operator is not for only statement, but rather for assignment or for expression (and break
is an only statement):
a = 5 if cond else 3 #OK
do() if cond else dont() #also OK
do() if cond else break #not OK
use normal if-else
statement to do statements:
if cond:
do()
else:
break
You cannot use break in Your loop logic can be re written using itertools.takewhile if you want a more succinct solution
digits = list(str(102))
dummy = list(str(102/2))
from itertools import takewhile
for d in takewhile(dummy.__contains__, digits):
dummy.remove(d)
You can also remove the need for the else using a for loop by reversing your logic, check if j is not in dummy breaking when that is True:
for j in digits:
if j not in dummy:
break
dummy.remove(j)
Also if you want to remove all occurrences of any of the initial elements from digits that are in dummy, remove won't do that for any repeating elements but using a list comp after creating a set of elements to remove will:
digits = str(102)
dummy = list(str(102/2))
st = set(takewhile(dummy.__contains__, digits))
dummy[:] = [d for d in dummy if d not in st]
print(dummy)
You can also iterate over a string so no need to call list on digits unless you plan on doing some list operations with it after.
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