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I'm attempting to serve a CSS file through my url.py file so I can use template tags in my CSS.
Here's my code.
Base.html:
<head>
...
<link rel="stylesheet" type="text/css" href="/site_media/css/wideTitle.css" />
urls.py:
(r'^site_media/css/wideTitle.css','lightbearers.views.viewWideTitle'),
views.py:
def viewWideTitle(request):
contentListAbout = About.objects.filter(Q(startDate__lte=datetime.now())).order_by('-startDate')
if len(contentListAbout) > 0:
contentAbout = contentListAbout[0]
else:
contentAbout = None
...
return render_to_response('wideTitle.css', {'contentAbout':contentAbout, ...},
context_instance=RequestContext(request))
settings.py:
TEMPLATE_DIRS = (
os.path.join(PROJECT_PARENT, "templates"),
os.path.join(PROJECT_PARENT, "media/css"),
)
wideTitle.css (in /media/css):
#wideTitle{
clear:both;
height:180px;
padding-left:0px;
background: url({{ contentAbout.headerImage.url }}) no-repeat top left;
}
I can access the CSS file by entering its URL in my browser, but the Base.html isn't reading it at all. I think I've got everything decent; I've looked here and here for tips. Anyone have ideas?
606
Is the generated stylesheet being served with the correct mime type? If not, the browser might not interpret it as CSS.
I can’t remember if render_to_response accepts content_type='text/css as an argument, but there is a way to set it if Django isn’t already using the correct mime type.
Edit: as @TommasoBarbugli pointed out, you want the mimetype argument for render_to_response.
(Firefox’s Firebug add-on, or the Web Inspector in Chrome/Safari, should be able to show you the stylesheet’s mime type.)
139
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