Using SUM on FLOAT data

Question

One table:
items(id, price)

Has one row:
id: 1, price: 565.8

SELECT price FROM items gives 565.8
SELECT SUM(price) FROM items gives 565.799987792969 instead of 565.8 which I'd expect.

Where does the 565.799987792969 come from?

Answer 1

You can use the ROUND or FORMAT function:

SELECT ROUND(SUM(price), 2) FROM items; 

Alternatively you can specify precision when defining a column, e.g. FLOAT(5,2).

Answer 2

I'm not sure what version you are using, but it sounds like this link describes what you are experiencing.

From the link:

mysql> select * from aaa; +----+------------+------+ | id | month_year | cost | +----+------------+------+ |  1 | 2002-05-01 | 0.01 | |  2 | 2002-06-01 | 1.65 | |  3 | 2002-07-01 | 0.01 | |  4 | 2002-01-01 | 0.01 | +----+------------+------+  mysql> select id, sum(cost) from aaa group by id; +----+---------------------+ | id | sum(cost)           | +----+---------------------+ |  1 | 0.00999999977648258 | |  2 |    1.64999997615814 | |  3 | 0.00999999977648258 | |  4 | 0.00999999977648258 | +----+---------------------+  The SUM function changes 0.01 to 0.00999999977648258. 

Floating point numbers are stored as approximate values; if you are storing a price, you are better off using a decimal datatype which stores precise values.