I couldn't get a grammar to work so I simplified it till it only parses an integer. Still can't get it to work. It is the following grammar:
template<typename Iterator>
struct rangeGrammar : qi::grammar<Iterator, int()>
{
rangeGrammar() :
rangeGrammar::base_type(number)
{
using qi::int_;
using qi::_1;
using qi::_val;
number = int_[_val = _1];
}
qi::rule<Iterator, int()> number;
};
It is supposed to just parse an integer (I know I could just tell the parse function to use int_ as the grammar, but I wan't to know what is wrong in this example).
My parse function is:
/* n is a std::string provided by the user */
rangeGrammar<std::string::const_iterator> grammar;
int num = 0;
qi::phrase_parse(n.start(), n.end(), grammar, num);
std::cout << "Number: " << num << std::endl;
I get the following compiler error:
/boost/spirit/home/qi/reference.hpp: In member function ‘bool boost::spirit::qi::reference::parse(Iterator&, const Iterator&, Context&, const Skipper&, Attribute&) const [with Iterator = __gnu_cxx::__normal_iterator >, Context = boost::spirit::context, boost::spirit::locals<> >, Skipper = boost::spirit::unused_type, Attribute = int, Subject = const boost::spirit::qi::rule<__gnu_cxx::__normal_iterator >, int(), boost::spirit::unused_type, boost::spirit::unused_type, boost::spirit::unused_type>]’: /boost/spirit/home/qi/parse.hpp:89:82: instantiated from ‘bool boost::spirit::qi::parse(Iterator&, Iterator, const Expr&, Attr&) [with Iterator = __gnu_cxx::__normal_iterator >, Expr = rangeGrammar<__gnu_cxx::__normal_iterator > >, Attr = int]’ ../parameter_parser.h:95:46: instantiated from here boost/spirit/home/qi/reference.hpp:43:71: error: no matching function for call to ‘boost::spirit::qi::rule<__gnu_cxx::__normal_iterator >, int(), boost::spirit::unused_type, boost::spirit::unused_type, boost::spirit::unused_type>::parse(__gnu_cxx::__normal_iterator >&, const __gnu_cxx::__normal_iterator >&, boost::spirit::context, boost::spirit::locals<> >&, const boost::spirit::unused_type&, int&) const’ cc1plus: warnings being treated as errors /boost/spirit/home/qi/reference.hpp:44:9: error: control reaches end of non-void function * exit status 1 *
Can't figure out what the problem is. Any help would be greatly appreciated.
A: There's nothing little wrong with the grammar, but you're using qi::phrase_parse
which requires a skipper. Use qi::parse
and the problem goes away.
Note 1: Using [_val=_1]
is completely redundant there; rules without semantic attributes enjoy automatic attribute propagation.
Note 2: You might want to use qi::match to do parsing like this:
#include <boost/spirit/include/qi_match.hpp>
const std::string input = "1234";
std::istringstream iss(input);
iss >> qi::match(qi::int_ [ std::cout << qi::_1 ]);
Finally For your interest, here's a skeleton 'doParse' function with running test that shows some more elements of good Qi practice:
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
namespace qi = boost::spirit::qi;
namespace phx = boost::phoenix;
template<typename Iterator>
struct rangeGrammar : qi::grammar<Iterator, int()>
{
rangeGrammar() : rangeGrammar::base_type(number)
{
number = qi::int_;
}
qi::rule<Iterator, int()> number;
};
bool doParse(const std::string& input)
{
typedef std::string::const_iterator It;
It f(begin(input)), l(end(input));
try
{
rangeGrammar<It> p;
int data;
bool ok = qi::parse(f,l,p,data);
if (ok)
{
std::cout << "parse success\n";
std::cout << "data: " << data << "\n";
}
else std::cerr << "parse failed: '" << std::string(f,l) << "'\n";
if (f!=l) std::cerr << "trailing unparsed: '" << std::string(f,l) << "'\n";
return ok;
} catch(const qi::expectation_failure<It>& e)
{
std::string frag(e.first, e.last);
std::cerr << e.what() << "'" << frag << "'\n";
}
return false;
}
int main()
{
bool ok = doParse("1234");
return ok? 0 : 255;
}
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