I guess it is not possible to invoke methods implemented in Scala traits from Java, or is there a way?
Suppose I have in Scala:
trait Trait { def bar = {} }
and in Java if I use it as
class Foo implements Trait { }
Java complains that Trait is not abstract and does not override abstract method bar() in Trait
In scala, trait is a collection of abstract and non-abstract methods. You can create trait that can have all abstract methods or some abstract and some non-abstract methods. A variable that is declared either by using val or var keyword in a trait get internally implemented in the class that implements the trait.
In Scala, we are allowed to implement the method(only abstract methods) in traits. If a trait contains method implementation, then the class which extends this trait need not implement the method which already implemented in a trait.
scala is compiled into Trait interface. Hence implementing Trait in Java is interpreted as implementing an interface - which makes your error messages obvious.
From Java perspective Trait.scala
is compiled into Trait
interface. Hence implementing Trait
in Java is interpreted as implementing an interface - which makes your error messages obvious. Short answer: you can't take advantage of trait implementations in Java, because this would enable multiple inheritance in Java (!)
Long answer: so how does it work in Scala? Looking at the generated bytecode/classes one can find the following code:
interface Trait { void bar(); } abstract class Trait$class { public static void bar(Trait thiz) {/*trait implementation*/} } class Foo implements Trait { public void bar() { Trait$class.bar(this); //works because `this` implements Trait } }
Trait
is an interfaceTrait$class
(do not confuse with Trait.class
) class is created transparently, which technically does not implement Trait
interface. However it does have a static bar()
method taking Trait
instance as argument (sort of this
)Foo
implements Trait
interfacescalac
automatically implements Trait
methods by delegating to Trait$class
. This essentially means calling Trait$class.bar(this)
.Note that Trait$class
is neither a member of Foo
, nor does Foo
extend it. It simply delegates to it by passing this
.
To continue the digression on how Scala works... That being said it is easy to imagine how mixing in multiple traits works underneath:
trait Trait1 {def ping(){}}; trait Trait2 {def pong(){}}; class Foo extends Trait1 with Trait2
translates to:
class Foo implements Trait1, Trait2 { public void ping() { Trait1$class.ping(this); //works because `this` implements Trait1 } public void pong() { Trait2$class.pong(this); //works because `this` implements Trait2 } }
Now it's easy to imagine how mixing in multiple traits overriding same method:
trait Trait {def bar(){}}; trait Trait1 extends Trait {override def bar(){}}; trait Trait2 extends Trait {override def bar(){}};
Again Trait1
and Trait2
will become interfaces extending Trait
. Now if Trait2
comes last when defining Foo
:
class Foo extends Trait1 with Trait2
you'll get:
class Foo implements Trait1, Trait2 { public void bar() { Trait2$class.bar(this); //works because `this` implements Trait2 } }
However switching Trait1
and Trait2
(making Trait1
to be last) will result in:
class Foo implements Trait2, Trait1 { public void bar() { Trait1$class.bar(this); //works because `this` implements Trait1 } }
Now consider how traits as stackable modifications work. Imagine having a really useful class Foo:
class Foo { def bar = "Foo" }
which you want to enrich with some new functionality using traits:
trait Trait1 extends Foo { abstract override def bar = super.bar + ", Trait1" } trait Trait2 extends Foo { abstract override def bar = super.bar + ", Trait2" }
Here is the new 'Foo' on steroids:
class FooOnSteroids extends Foo with Trait1 with Trait2
It translates to:
interface Trait1 { String Trait1$$super$bar(); String bar(); } abstract class Trait1$class { public static String bar(Trait1 thiz) { // interface call Trait1$$super$bar() is possible // since FooOnSteroids implements Trait1 (see below) return thiz.Trait1$$super$bar() + ", Trait1"; } }
public interface Trait2 { String Trait2$$super$bar(); String bar(); } public abstract class Trait2$class { public static String bar(Trait2 thiz) { // interface call Trait2$$super$bar() is possible // since FooOnSteroids implements Trait2 (see below) return thiz.Trait2$$super$bar() + ", Trait2"; } }
class FooOnSteroids extends Foo implements Trait1, Trait2 { public final String Trait1$$super$bar() { // call superclass 'bar' method version return Foo.bar(); } public final String Trait2$$super$bar() { return Trait1$class.bar(this); } public String bar() { return Trait2$class.bar(this); } }
So the whole stack invocations are as follows:
And the result is "Foo, Trait1, Trait2".
If you've managed to read everything, an answer to the original question is in the first four lines...
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