Using replace() function to replace multiple texts(strings) at once in Python

Question

Here's my code:

start_j = raw_input('Enter a name: ')
start_j = start.replace("A", "J")
start_j = start.replace("B", "J")
start_j = start.replace("C", "J")
print "Your name is " + start_j

Is there anyway to put all the alphabets in one list so that I wouldn't have to repeat the same process again and again until I reach letter "Z" I tried using loops, but I still can't seem to get the right way to do it.

Here's a scenario: The user will be prompted to input a name. If the name contains a letter other than "J", it will be automatically replaced using the replace() function. Hence it will print out the input starting with J

Here's an example:

site = raw_input('Enter your website: ')
site = site.replace("http://", "")
site = site.replace("https://", "")
site = site.replace("ftp://", "")
print "Your website is: " + site

An expected input would be http://www.google.com So the expected out would become:

Enter your website: http://www.google.com
Your website is: www.google.com

I'm looking for a way to put "http://", "https://", "ftp://" all in one list so I wouldn't have to enter

site = site.replace("something", "something)

many times

Answer 1

You could use a regex to replace all of the letters at once:

>>> import re
>>> re.sub(r'[A-Z]', 'J', 'This Is A Test Name')
'Jhis Js J Jest Jame'

---

(After edit): You can use .startswith() and string slicing:

>>> name = 'A Name'
>>> 
>>> if not name.startswith('J'):
...     name = 'J' + name[1:]
... 
>>> name
'J Name'

Although I'm not sure why you'd even need to check with .startswith(). Either way, the result will be the same.

Answer 2

You can use this:

remove_from_start = ["http://", "https://", "ftp://"]
for s in remove_from_start:
    if site.startswith(s):
        site = site[len(s):]
        break

Or a regular expression based solution:

import re
regex = '^(https?|ftp)://'
site = re.sub(regex, '', site)