Using RegEx how do I remove the trailing zeros from a decimal number

Question

I'm needing to write some regex that takes a number and removes any trailing zeros after a decimal point. The language is Actionscript 3. So I would like to write:

var result:String = theStringOfTheNumber.replace( [ the regex ], "" );

So for example:

3.04000 would be 3.04

0.456000 would be 0.456 etc

I've spent some time looking at various regex websites and I'm finding this harder to resolve than I initially thought.

Answer 1

Regex:

^(\d+\.\d*?[1-9])0+$

OR

(\.\d*?[1-9])0+$

Replacement string:

$1

DEMO

Code:

var result:String = theStringOfTheNumber.replace(/(\.\d*?[1-9])0+$/g, "$1" );

Answer 2

What about stripping the trailing zeros before a \b boundary if there's at least one digit after the .

(\.\d+?)0+\b

And replace with what was captured in the first capture group.

$1

See test at regexr.com

Answer 3

What worked best for me was

^([\d,]+)$|^([\d,]+)\.0*$|^([\d,]+\.[0-9]*?)0*$

For example,

s.replace(/^([\d,]+)$|^([\d,]+)\.0*$|^([\d,]+\.[0-9]*?)0*$/, "$1$2$3");

This changes

1.10000 => 1.1
1.100100 => 1.1001
1.000 => 1
1 >= 1