Using React.lazy with TypeScript

Question

I am trying to use React.lazy for code splitting in my TypeScript React app.

All I am doing is changing that line:

import {ScreensProductList} from "./screens/Products/List"; 

to this line:

const ScreensProductList = lazy(() => import('./screens/Products/List')); 

But the import('./screens/Products/List') part triggers a TypeScript error, stating:

Type error: Type 'Promise<typeof import("/Users/johannesklauss/Documents/Development/ay-coding-challenge/src/screens/Products/List")>' is not assignable to type 'Promise<{ default: ComponentType<any>; }>'.   Property 'default' is missing in type 'typeof import("/Users/johannesklauss/Documents/Development/ay-coding-challenge/src/screens/Products/List")' but required in type '{ default: ComponentType<any>; }'. 

I am not quite sure what I am supposed to do here to get it to work.

Answer 1

You should do export default class {...} from the ./screens/Products/list instead of export class ScreensProductList {...}.

Or, alternatively, you can do:

const ScreensProductList = lazy(() =>   import('./screens/Products/List')     .then(({ ScreensProductList }) => ({ default: ScreensProductList })), );