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I have a text file structure as:
date
downland
user
date data1 date2
201102 foo bar 200 50
201101 foo bar 300 35
So first six lines of file are not needed. filename:dnw.txt
f = open('dwn.txt', 'rb')
How do I "split" this file starting at line 7 to EOF?
393
Method 1: fileobject.readlines() A file object can be created in Python and then readlines() method can be invoked on this object to read lines into a stream. This method is preferred when a single line or a range of lines from a file needs to be accessed simultaneously.
Method 1: Read a File Line by Line using readlines() readlines() is used to read all the lines at a single go and then return them as each line a string element in a list. This function can be used for small files, as it reads the whole file content to the memory, then split it into separate lines.
with open('dwn.txt') as f:
for i in xrange(6):
f, next()
for line in f:
process(line)
Update: use next(f) for python 3.x.
180
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