I have the following situation:
NSArray(
NSArray(
string1,
string2,
string3,
string4,
string5,
)
,
NSArray(
string6,
string7,
string8,
string9,
string10,
)
)
Now I need a predicate that returns the array that contains a specific string. e.g. Filter Array that contains string9 -> I should get back the entire second array because I need to process the other strings inside that array. Any ideas?
Just for completeness: It can be done using predicateWithFormat:
:
NSArray *array = @[
@[@"A", @"B", @"C"],
@[@"D", @"E", @"F"],
];
NSString *searchTerm = @"E";
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY SELF == %@", searchTerm];
NSArray *filtered = [array filteredArrayUsingPredicate:predicate];
NSLog(@"%@", filtered);
Output:
( ( D, E, F ) )
From what I know you can't do it as a one-liner so instead of using predicateWithFormat:
you should use predicateWithBlock:
Something like this should do what you want
NSString *someString = @"Find me"; // The string you need to find.
NSArray *arrayWithArrayOfStrings = @[]; // Your array
[arrayWithArrayOfStrings filteredArrayUsingPredicate:[NSPredicate predicateWithBlock:^BOOL(NSArray *evaluatedArray, NSDictionary *bindings) {
return [evaluatedArray indexOfObject:someString] != NSNotFound;
}]];
Update: Martin R proved me wrong :)
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