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Using mysql aliases to select columns from 2 tables

I have 2 tables: table_a and table_b. Both contain a column named 'open'.

table_a
+-------+
| open  |
+-------+
| 36.99 |
| 36.85 |
| 36.40 |
| 36.33 |
| 36.33 |
+-------+

table_b 
+------+
| open |
+------+
| 4.27 |
| 4.46 |
| 4.38 |
| 4.22 |
| 4.18 |
+------+

I'd like to write a query that returns the following

+-------++------+
| open  || open |
+-------++------+
| 36.99 || 4.27 |
| 36.85 || 4.46 |
| 36.40 || 4.38 |
| 36.33 || 4.22 |
| 36.33 || 4.18 |
+-------++------+

I attempt the following query:

select a.open, b.open from  table_a a, table_b b;

This returns a table with every value of table_b.open for each value of table_a.open

+-------++------+
| open  || open |
+-------++------+
| 36.99 || 4.27 |
| 36.99 || 4.46 |
| 36.99 || 4.38 |
| 36.99 || 4.22 |
|   ... || 4.18 |
+   ... ++------+

I can see I'm misunderstanding proper usage of aliases here. Any ideas?

like image 890
rocketas Avatar asked Mar 03 '13 20:03

rocketas


1 Answers

It is not an alias problem that you have. You are performing a CROSS JOIN on the table which creates a cartesian result set.

This multiplies your result set so every row from table_a is matched directly to every row in table_b.

If you want to JOIN the tables together, then you need some column to join the tables on.

If you have a column to JOIN on, then your query will be:

select a.open as a_open,
  b.open as b_open
from table_a a
inner join table_b b
  on a.yourCol = b.yourCol

If you do not have a column that can be used to join on, then you can create a user-defined variable to do this which will create a row number for each row.

select 
   a.open a_open, 
   b.open b_open
from
(
  select open, a_row
  from
  (
    select open,
      @curRow := @curRow + 1 AS a_row
    from table_a
    cross join (SELECT @curRow := 0) c
  ) a
) a
inner join
(
  select open, b_row
  from 
  (
    select open,
      @curRow := @curRow + 1 AS b_row
    from table_b 
    cross join (SELECT @curRow := 0) c
  ) b
) b
  on a.a_row = b.b_row;

See SQL Fiddle with Demo

like image 124
Taryn Avatar answered Oct 29 '22 14:10

Taryn