Using Moq setting up all methods of a mock equally

Question

Let's assume I have the interface

public interface A {
  int Foo1();

  int Foo2();

  int Foo3();
}

and a testing method with a mock (using Moq) like

Mock<A> mock = new Mock<A>();

Now there are basically two testing scenarios:

Scenario 1

I want to test what my system-under-test does if the interface implementation throws a specific exception on any method. So I want to setup all methods to throw the same exception like

mock.Setup(x => x.Foo1()).Throws(new Exception());
mock.Setup(x => x.Foo2()).Throws(new Exception());
mock.Setup(x => x.Foo3()).Throws(new Exception());

Scenario 2

I want to test what my system-under-test does if the methods return any number. So I could think of setup the mock like

mock.Setup(x => x.Foo1()).Returns(1);
mock.Setup(x => x.Foo2()).Returns(1);
mock.Setup(x => x.Foo3()).Returns(1);

Reason: I have many different unit tests for the system-under-test. Some of them are tests for business logic where it makes a difference e.g. what values are returned. But some are just small tests for general behavior, e.g. if the system-under-test throws an exception if one of the used components throws one. Or the opposite, that the system-under-test throws no exception if all components behave as expected. And for these small tests I'm using code like above right now.

Question: Is there a smarter way to initialize all (matching) methods of a Mock the same way? Something like

mock.SetupAll().Throws(new Exception());

or

mock.SetupAll<int>().Returns(1);

(which means: setup those methods which have a return type of int)?

Answer 1

This can be achieved with SetReturnsDefault, like:

mock.SetReturnsDefault(1);

See SetReturnsDefault in the source for more info: Moq on github