First off, apologies for the lame question. I am reading the `Scala for the Impatient' religiously and trying to solve all the exercise questions (and doing some minimal exploration)
Background : The exercise question goes like - Setup a map of prices for a number of gizmos that you covet. Then produce a second map with the same keys and the prices at a 10% discount.
Unfortunately, at this point, most parts of the scaladoc are still cryptic to me but I understand that the map function of the Map
takes a function and returns another map after applying a function (I guess?) - def map[B](f: (A) ⇒ B): HashMap[B]
. I tried googling but couldnt get much useful results for map function for Map in scala
:-)
My Question:
As attempted in my variation 3, does using map
function for this purpose make any sense or should I stick with the variation 2 which actually solves my problem.
Code :
val gizmos:Map[String,Double]=Map("Samsung Galaxy S4 Zoom"-> 1000, "Mac Pro"-> 6000.10, "Google Glass"->2000)
//1. Normal for/yield
val discountedGizmos=(for ((k,v)<-gizmos) yield (k, v*0.9)) //Works fine
//2. Variation using mapValues
val discGizmos1=gizmos.mapValues(_*0.9) //Works fine
//3. Variation using only map function
val discGizmos2=gizmos.map((_,v) =>v*0.9) //ERROR : Wrong number of parameters: expected 1
Scala Map get() method with exampleThe get() method is utilized to give the value associated with the keys of the map. The values are returned here as an Option i.e, either in form of Some or None. Return Type: It returns the keys corresponding to the values given in the method as argument.
Map class explicitly. If you want to use both mutable and immutable Maps in the same, then you can continue to refer to the immutable Map as Map but you can refer to the mutable set as mutable. Map. While defining empty map, the type annotation is necessary as the system needs to assign a concrete type to variable.
map() creates a new array from calling a function for every array element. map() calls a function once for each element in an array. map() does not execute the function for empty elements.
In this case, mapValues does seem the more appropriate method to use. You would use the map method when you need to perform a transformation that requires knowledge of the keys (eg. converting a product reference into a product name, say).
That said, the map method is more general as it gives you acces to both the keys and values for you to act upon, and you could emulate the mapValues method by simply transforming the values and passing the keys through untouched - and that is where you are going wrong in your code above. To use the map method correctly, you should be producing a (key, value) pair from your function, not just a key:
val discGizmos2=gizmos.map{ case (k,v) => (k,v*0.9) } // pass the key through unchanged
It can be also:
val discGizmos2 = gizmos.map(kv => (kv._1, kv._2*0.9))
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