I have simple dataframe:
import pandas as pd
frame = pd.DataFrame(np.random.randn(4, 3), columns=list('abc'))
Thus for example:
a b c
0 -0.813530 -1.291862 1.330320
1 -1.066475 0.624504 1.690770
2 1.330330 -0.675750 -1.123389
3 0.400109 -1.224936 -1.704173
And then I want to create column “d” that contains value from “c” if c is positive. Else value from “b”.
I am trying:
frame['d']=frame.apply(lambda x: frame['c'] if frame['c']>0 else frame['b'],axis=0)
But getting “ValueError: ('The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().', 'occurred at index a')
I was trying to google how to solve this, but did not succeed. Any tip please?
Apply Lambda Function to Single Column You can apply the lambda function for a single column in the DataFrame. The following example subtracts every cell value by 2 for column A – df["A"]=df["A"]. apply(lambda x:x-2) . Yields below output.
Using apply() method If you need to apply a method over an existing column in order to compute some values that will eventually be added as a new column in the existing DataFrame, then pandas. DataFrame. apply() method should do the trick.
is that what you want?
In [300]: frame[['b','c']].apply(lambda x: x['c'] if x['c']>0 else x['b'], axis=1)
Out[300]:
0 -1.099891
1 0.582815
2 0.901591
3 0.900856
dtype: float64
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