Using greater than operator with subprocess.call

Question

What I am trying to do is pretty simple. I want to call the following command using python's subprocess module.

cat /path/to/file_A > file_B

The command simply works and copies the contents of file_A to file_B in current working directory. However when I try to call this command using the subprocess module in a script it errors out. Following is what I am doing:

import subprocess

subprocess.call(["cat", "/path/to/file_A", ">", "file_B"])

and I get the following error:

cat: /path/to/file_A: No such file or directory
cat: >: No such file or directory
cat: file_B: No such file or directory

what am I doing wrong ? How can I use the greater than operator with subprocess modules call command ?

Answer 1

> output redirection is a shell feature, but subprocess.call() with an args list and shell=False (the default) does not use a shell.

You'll have to use shell=True here:

subprocess.call("cat /path/to/file_A > file_B", shell=True)

or better still, use subprocess to redirect the output of a command to a file:

with open('file_B', 'w') as outfile:
    subprocess.call(["cat", "/path/to/file_A"], stdout=outfile)

If you are simply copying a file, use the shutil.copyfile() function to have Python copy the file across:

import shutil

shutil.copyfile('/path/to/file_A', 'file_B')