This command will print a
.
echo "line1 a b c" | awk '{ print $2 }'
If I change single quotes to double quotes, like this, it will print whole line.
echo "line1 a b c" | awk "{ print $2 }"
Why? I know I should use single quotes, but why is the whole line printed if I use double quotes?
If the awk
command is single quoted, the $2
is not interpreted by the shell, but is instead passed as the literal string $2
to awk
. awk
will then print
the second space delimited token in the input string, which in this case is a
.
echo "line1 a b c" | awk '{ print $2 }' # prints the second space-delimited token
> a
If the awk
command is double quoted, the $2
is interpreted by the shell. Because $2
is empty (in this case), the empty string is substituted. awk
sees a command which looks like awk "{ print }"
, which is an instruction to print everything.
echo "line1 a b c" | awk '{ print }' # prints all input
> line1 a b c
It is also possible to use double qotes, and escape the $
, which will cause the $
to not be interpreted by the shell, and instead the $2
string will be passed to awk
.
echo "line1 a b c" | awk "{ print \$2 }" # prints the second space-delimited token
> a
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