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I want to get a string of numbers one by one, so I'm using a while loop
with cin.get() as the function that gets my digits one by one.
But cin.get() gets the digits as chars and even though I'm trying to use
casting I can't get my variables to contain the numrical value and not the ascii value
of the numbers I get as an input.
382
To declare an int variable in C++ you need to first write the data type of the variable – int in this case. This will let the compiler know what kind of values the variable can store and therefore what actions it can take. Next, you need give the variable a name. Lastly, don't forget the semicolon to end the statement!
get() is used for accessing character array. It includes white space characters. Generally, cin with an extraction operator (>>) terminates when whitespace is found.
Apply isdigit() function that checks whether a given input is numeric character or not. This function takes single argument as an integer and also returns the value of type int.
Using the stoi() function The stoi() function converts a string data to an integer type by passing the string as a parameter to return an integer value. The stoi() function contains an str argument. The str string is passed inside the stoi() function to convert string data into an integer value.
cin.get can’t parse numbers. You could do it manually – but why bother re-implementing this function, since it already exists?*
int number;
std::cin >> number;
In general, the stream operators (<< and >>) take care of formatted output and input, istream::get on the other hand extracts raw characters only.
* Of course, if you have to re-implement this functionality, there’s nothing for it.
To get the numeric value from a digit character, you can exploit that the character codes of the decimal digits 0–9 are consecutive. So the following function can covert them:
int parse_digit(char digit) {
return digit - '0';
}
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