Using a Python Script in Java (Eclipse)

Question

I've been looking to incorporate a Python Script a friend made for me into a Java application that I am trying to develop. After some trial and error I finally found out about 'Jython' and used the PythonInterpreter to try and run the script.

However, upon trying to run it, I am getting an error within the Python Script. This is odd because when I try run the script outside of Java (Eclipse IDE in this case), the script works fine and does exactly what I need it to (extract all the images from the .docx files stored in its same directory).

Can someone help me out here?

Java:

import org.python.core.PyException;
import org.python.util.PythonInterpreter;

public class SPImageExtractor
{
    public static void main(String[] args) throws PyException
    {   
        try
        {
            PythonInterpreter.initialize(System.getProperties(), System.getProperties(), new String[0]);
            PythonInterpreter interp = new PythonInterpreter();
            interp.execfile("C:/Documents and Settings/user/workspace/Intern Project/Proposals/Converted Proposals/Image-Extractor2.py");
        }
        catch(Exception e)
        {
            System.out.println(e.toString());
            e.printStackTrace();
        }
    }
}

---

Java Error regarding Python Script:

Traceback (most recent call last):
File "C:/Documents and Settings/user/workspace/Intern Project/Proposals/Converted Proposals/Image-Extractor2.py", line 19, in thisDir,_ = path.split(path.abspath(argv[0])) IndexError: index out of range: 0 Traceback (most recent call last):
File "C:/Documents and Settings/user/workspace/Intern Project/Proposals/Converted Proposals/Image-Extractor2.py", line 19, in thisDir,_ = path.split(path.abspath(argv[0])) IndexError: index out of range: 0

---

Python:

from os import path, chdir, listdir, mkdir, gcwd
from sys import argv
from zipfile import ZipFile
from time import sleep

#A few notes -
#(1) when I do something like " _,variable = something ", that is because
#the function returns two variables, and I only need one.  I don't know if it is a
#common convention to use the '_' symbol as the name for the unused variable, but
#I saw it in some guy's code in the past, and I started using it.
#(2) I use "path.join" because on unix operating systems and windows operating systems
#they use different conventions for paths like '\' vs '/'.  path.join works on all operating
#systems for making paths.

#Defines what extensions to look for within the file (you can add more to this)
IMAGE_FILE_EXTENSIONS = ('.bmp', '.gif', '.jpg', '.jpeg', '.png', '.tif', '.tiff')

#Changes to the directory in which this script is contained
thisDir = getcwd()
chdir(thisDir)

#Lists all the files/folders in the directory
fileList = listdir('.')
for file in fileList:

    #Checks if the item is a file (opposed to being a folder)
    if path.isfile(file):

        #Fetches the files extension and checks if it is .docx
        _,fileExt = path.splitext(file)
        if fileExt == '.docx':

            #Creates directory for the images
            newDirectory = path.join(thisDir, file + "-Images")
            if not path.exists(newDirectory):
                mkdir(newDirectory)

            currentFile = open(file,"r")
            for line in currentFile:
                print line

            sleep(5)



            #Opens the file as if it is a zipfile
            #Then lists the contents
            try:
                zipFileHandle = ZipFile(file)
                nameList = zipFileHandle.namelist()

                for archivedFile in nameList:
                    #Checks if the file extension is in the list defined above
                    #And if it is, it extracts the file
                    _,archiveExt = path.splitext(archivedFile)
                    if archiveExt in IMAGE_FILE_EXTENSIONS:
                        zipFileHandle.extract(archivedFile, newDirectory)
            except:
                pass

Answer 1

My guess is that you don't get command line arguments if the interpreter is called (well not that surprisingly, where should it get the correct values? [or what would be the correct value?]).

os.getcwd()

Return a string representing the current working directory.

Would return the working dir, but presumably that's not what you want.

Not tested, but I think os.path.dirname(os.path.realpath( __ file__)) should work presumably (Note: remove the space there; I should look at the formatting options in detail some time~)