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a = [] a.append(lambda x:x**0)
a.append(lambda x:x**1)
a[0](2), a[1](2), a[2](2)... spits out 1, 2, 4, ...
b=[]
for i in range(4)
b.append(lambda x:x**i)
b[0](2), b[1](2), b[2](2)... spits out 8, 8, 8, ...
In the for loop, the i is being passed to lambda as a variable, so when I call it, the last value of i is used instead of the code running as it does with a[]. (ie b[0] should use x^1, b[1] should use x^2, ...)
How can I tell lambda to pick up the value of i instead of the variable i itself.
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That's not more than one return, it's not even a single return with multiple values. It's one return with one value (which happens to be a tuple).
Yes, you can modify local variables from inside lambdas (in the way shown by the other answers), but you should not do it.
To set environment variables in the Lambda consoleOpen the Functions page of the Lambda console. Choose a function. Choose Configuration, then choose Environment variables. Under Environment variables, choose Edit.
Because the local variables declared outside the lambda expression can be final or effectively final. The rule of final or effectively final is also applicable for method parameters and exception parameters. The this and super references inside a lambda expression body are the same as their enclosing scope.
Ugly, but one way:
for i in range(4)
b.append(lambda x, copy=i: x**copy)
You might prefer
def raiser(power):
return lambda x: x**power
for i in range(4)
b.append(raiser(i))
(All code untested.)
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